The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $7 and each adult ticket sells for $9.50. There was a total of $883.50 in revenue from all ticket sales and the drama club sold 27 more adult tickets than student tickets. Determine the number of student tickets sold and the number of adult tickets sold.

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Answer:

If a = the number of adult tickets sold, then (a + 20) = the number of student tickets sold

a + (a + 20) = 240

2a + 20 = 240

2a = 220

a = 110

There were 110 adult and 110 + 20 = 130 student tickets sold

Step-by-step explanation:

The number of student tickets sold is [tex]38[/tex] and the number of adult tickets sold is [tex]65[/tex].

Price of student's ticket [tex]=[/tex] $[tex]7[/tex].

Price of adult's ticket [tex]=[/tex] $[tex]9.50[/tex].

Let the number of student's tickets sold be [tex]x[/tex].

Then the number of adult's tickets sold be [tex]27+x[/tex].

Total revenue [tex]=[/tex] $ [tex]883.50[/tex]

[tex]7 \times x + 9.50 (27 + x) = 883.50[/tex]

[tex]7x + 256.50 + 9.50x = 883.50[/tex]

[tex]16.50 x = 883.50 - 256.50[/tex]

[tex]16.50 x = 627[/tex]

[tex]x = \frac{627}{16.50}[/tex]

[tex]x = 38.[/tex]

So, the number of student's tickets sold is [tex]38[/tex].

And, the number of adult's tickets sold be [tex]27+38 = 27+38=65[/tex].

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