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Write the standard equation of the circle below.
image of a circle with its center at the coordinate 1, negative 2 and radius 3
(x - 1)^2 + (y + 2)^2 = 9

(x + 1)^2 + (y - 2)^2 = 3

(x - 1)2 + (y + 2)2 = 3

(x + 2)^2 + (y - 1)^2 = 9

Write the standard equation of the circle below.
image of a circle with its center at the coordinate zero, negative 2 and radius 3

x^2 + (y - 2)^2 = 9

(x + 2)^2 + y^2 = 9

x^2 + (y + 2)^2 = 3

x^2 + (y + 2)^2 = 9

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bhuvna789456

Equation of the first circle is (x - 1)² + (y + 2)² = 9 and that of the second circle is x² + (y + 2)² = 9

Step-by-step explanation:

  • Step 1: Given the center of the first circle (h,k) = (1,-2) and radius, r = 3

Equation of the circle = (x-h)² + (y-k)² = r²

⇒ (x - 1)² + (y + 2)² = 9

  • Step 2: Given the center of the first circle (h,k) = (0,-2) and radius, r = 3

⇒ x² + (y + 2)² = 9

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