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Water is being heated in a closed pan on top of a range whilebeing stirred by a paddle wheel. During the process 30kJ of heat istransferred to the water and 5kJ of heat is lost to the surroundingair. The paddle wheel works amounts to 500 N*m. The initialinternal energy of the system is 10kJ. Determine the final internalenergy (kJ) of the system.

Respuesta :

Hashirriaz830

Answer:

38 kJ

Explanation:

The solution is obtained using the energy balance:  

ΔE=E_in-E_out

U_2-U_1=Q_in+W_in-Q_out

U_2=U_1+Q_in+W_in-Q_out

      =38 kJ

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