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Calculate the potential difference two charges when 6 joules of energy is needed to bring a charge of 0.01C close to the other charge.

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isaacoranseola

Answer: 1200 volts

Explanation:

Given that

W = 1/2 × QV

Where q is the charge in coulombs = 0.01 C

W = energy in the capacitor

V = potential difference in volts

Hence,

W = 6 = 1/2 × 0.01 × V

6×2 = 0.01 ×V

12 = 0.01 V

V = 12÷ 0.01

V = 1200 volts

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