A chemist measures the temperature in degrees Fahrenheit of a chemical

compound every hour. The temperatures approximate a geometric sequence where

an is the temperature at a given hour, and n is the hour. At hour 4, the temperature is

70 °F and at hour 6 the temperature is 80 °F.


Pls include the value of A1 A4 A6 and r thanks

Respuesta :

Answer:

[tex]A_{1}=57^{0}F; A_{4}=70^{0}F; A_{6}=80^{0}F; r=1.07[/tex]

Step-by-step explanation:

The formula for calculating the nth term of a Geometric Sequence is given as: [tex]A_{n}=ar^{n-1}[/tex] where n is the number of term, r=common ratio and a=first term.

At hour 4, the temperature is [tex]70^{0}[/tex]F

[tex]A_{4}=70, n=4\\70=ar^{4-1}=ar^{3}[/tex].......(i)

At hour 6 the temperature is 80°F.

[tex]A_{6}=80, n=6\\80=ar^{6-1}=ar^{5}[/tex]......(ii)

Solving (i) and (ii) simultaneously

[tex]\frac{80}{70}=\frac{ar^{5}}{ar^{3}} \\x^{2} r^{2} =\frac{8}{7}\\r=\sqrt{\frac{8}{7}}=1.07[/tex]

Plugging r into equation (i), we could use (ii) as well,

[tex]70=ar^{3}[/tex]

[tex]70=a(\sqrt{\frac{8}{7}})^{3}[/tex]

[tex]a=\frac{70}{\sqrt{(\frac{8}{7}})^{3}}[/tex]

[tex]a=\frac{245}{8}\sqrt{\frac{7}{2} }[/tex] =57.29

Therefore:

[tex]A_{1}=57^{0}F; A_{4}=70^{0}F; A_{6}=80^{0}F; r=1.07[/tex]

Answer:

The other user gave an amazing explanation but their final answer is a bit confusing, so to sum it up, here's the answer: 57(1.07)

Have a wonderful day!

Step-by-step explanation: