Respuesta :
Answer:
Therefore the solubility of CaSO₄ in Na₂SO₄ is =907.12 g/L.
Explanation:
CaSO₄ → Ca²⁺ + SO₄²⁻
Initially 0 0 0
Finally s s s
[tex]K_{sp}=[Ca^{2+}][SO_4^{2-}][/tex]........(1)
Na₂SO₄ → Na²⁺ + SO₄²⁻
Given, the concentration of Na₂SO₄ is 0.30 M .
Then [Na²⁺] = [SO₄²⁻] = 0.30
[tex]K_{sp}=2.0\times 10^{-5}[/tex]
Putting the value of [tex]K_{sp}[/tex] and [SO₄²⁻] in equation (1)
[tex]2.0\times 10^{-5}= [Ca^{2+}]0.30[/tex]
[tex]\Rightarrow [Ca^{2+}]=\frac{2.0\times 10^{-5}}{0.30}[/tex]
= 6.67×10⁻⁵
The atomic mass of CaSO₄ is 136 g/mol
Therefore the solubility of CaSO₄ in Na₂SO₄ is = (6.67×10⁻⁵×136)g/L
=907.12 g/L
