Answer:
The amount of energy produced by consuming 1 kg of fuel in nuclear fusion is [tex]1.0008\times 10^8 kWh[/tex] kWh.
Explanation:
Mass of fuel = 1 kg = 1000 g
Moles of fuel = [tex]\frac{1000 g}{5 g/mol}=200 mole[/tex]
The loss of mass in nuclear fusion is 0.02 g per mole of fuel
Loss of mass in nuclear fusion by consuming 200 mole : m
[tex]m=0.02 g/mol\times 200 mol = 4 g=4\times 0.001 kg[/tex]
1 g = 0.001 kg
Energy produced during this process can be determined by mass energy equation :
[tex]E=mc^2[/tex]
[tex]E=4\times 0.001 kg\times (3\times 10^8 m/s)^2=3.6\times 10^{14} J[/tex]
[tex]1 J = 2.78\times 10^{-7} kWh[/tex]
[tex]E=3.6\times 10^{14}\times 2.78\times 10^{-7} kWh=1.0008\times 10^8 kWh[/tex]
The amount of energy produced by consuming 1 kg of fuel in nuclear fusion is [tex]1.0008\times 10^8 kWh[/tex] kWh.
