Respuesta :
Answer:
The amplitude of the wave is 0.02 m.
Explanation:
Given that,
Maximum speed = 2.0 m/s
Maximum acceleration = 200 m/s²
We need to calculate the angular frequency
Using formula of angular frequency
[tex]\omega=\dfrac{a_{max}}{v_{max}}[/tex]
Put the value into the formula
[tex]\omega=\dfrac{200}{2.0}[/tex]
[tex]\omega=100\ rad/s[/tex]
We need to calculate the amplitude of the wave
Using formula of velocity
[tex]v_{max}=A\omega[/tex]
[tex]A=\dfrac{v_{max}}{\omega}[/tex]
Put the value into the formula
[tex]A=\dfrac{2.0}{100}[/tex]
[tex]A=0.02\ m[/tex]
Hence, The amplitude of the wave is 0.02 m.
The amplitude of the wave is 0.02 m.
Given that,
- A particle on the string has a maximum speed of 2.0 m/s and a maximum acceleration of 200 m/s2.
Calculation of amplitude of the wave:
The angular frequency should be
[tex]= 200 \div 2[/tex]
= 100 rad/s
Now the amplitude is
[tex]= 2 /100[/tex]
= 0.02m
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