Answer:
The magnitude of the electric field in the second case will be [tex]\frac{1}{8}[/tex] of the electric field in the first case
Explanation:
The electric field at a distance [tex]r_1[/tex] < R from the center of the sphere is given by
the formula [tex]E_1[/tex] = [tex]\frac{kQr_1}{R^3}[/tex]
where R is the radius of the sphere, and, Q is the charge uniformly distributed on the sphere.
It is given that the same charge Q is distributed uniformly throughout a sphere of radius 2R and we have to find the electric field at same distance [tex]r_1[/tex] from the center.
In the second case the electric field will be given by
[tex]E_2[/tex] = [tex]\frac{kQr_1}{(2R)^3} = \frac{kQr_1}{8R^3} =\frac{1}{8} \frac{kQr_1}{R^3} = \frac{1}{8} E_1[/tex]
Therefore the magnitude of the electric field in the second case will be [tex]\frac{1}{8}[/tex] of the electric field in the first case.