Respuesta :
Hello,
(2x²+7x-3)/(2x+5)=(2x²+5x+2x-3)/(2x+5)
=x(2x+5)/(2x+5)+ (2x+5-5-3)/(2x+5)
=(x+1)/(2x+5)-8/(2x+5)
==> 2x²+7x-3=(x+1)(2x+5)-8
Quotient=x+1
remainder=-8
(2x²+7x-3)/(2x+5)=(2x²+5x+2x-3)/(2x+5)
=x(2x+5)/(2x+5)+ (2x+5-5-3)/(2x+5)
=(x+1)/(2x+5)-8/(2x+5)
==> 2x²+7x-3=(x+1)(2x+5)-8
Quotient=x+1
remainder=-8
Answer:
The answer is D
Step-by-step explanation:
I just took the test and the guy who answered before me is correct its just hard to see