ShawnaMlangeni ShawnaMlangeni

30-06-2016
Mathematics

contestada

-3y(-4y)=32+(x^0+y^0)^5

Respuesta :

30-06-2016

Any number to the power of 0 equals 1. So, we can rewrite the equation as follows:
[tex]12y=32+2^{5}=32+32=64[/tex]
[tex]y=\frac{64}{12}=5\frac{1}{3}[/tex]

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