10gbarter
10gbarter
29-06-2016
Mathematics
contestada
e^0.5ln9=? no calculator
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Аноним
Аноним
29-06-2016
[tex]e^{0.5\ln 9}=e^\ln{9^{0.5}}=9^{0.5}= \sqrt{9} =3[/tex]
Use the property of logs: a ln b = ln (b^a)
Also e and log are inverses, so the cancel each other
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