Respuesta :
First term a=0
Fourth term= 12(4-1)3
=12*9
=108
10th term=12(10-1)3
=12*9*3
= 324
Fourth term= 12(4-1)3
=12*9
=108
10th term=12(10-1)3
=12*9*3
= 324
Answer:
No option suits this answer.
Step-by-step explanation:
Given is an arithmetic sequence with general term formula in n as
[tex]a_n = 12(n-1)+3[/tex]
We can find any general term by substituting for n
n =1
[tex]a_1 = 12(1-1)(3)=0[/tex]
I term is 0
II term is got by substituting n =2
[tex]a_2=12(2-1)3=36[/tex]
Hence common difference
[tex]d=a_2-a_1\\d=36-0 =36[/tex]
Hence the successive term would increase by 36
4th term
=[tex]a_4 =12(3)(3) =108\\a_10 = 12(9)(3) = 324[/tex]