shifter1020S
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. If measurements of a gas are 75L and 300 kilopascals and then the gas is measured a second time and found to be 50L, describe what had to happen to the pressure (if temperature remained constant). Include which law supports this observation.

Respuesta :

olemakpadu
By Boyle's law:

P₁V₁ = P₂V₂

300*75 = P₂*50

P₂*50= 300*75

P₂ = 300*75/50 = 450

P₂ = 450 kiloPascals.

The pressure has increased as a result of compression of gas.

Boyle's Law supports this observation.
wiseowl2018

Answer:

The pressure increased to 450 Kilo pascals.

Explanation:

This the condition of Boyle's law:

P1V1 = P2V2

By putting values in above formula:

= 300 * 75 = P2 * 50

= P = 300 * 75/50

= p = 450 Kilo pascals

In this question description, two variables volume and pressure are involved while the temperature remains constant. So it is the condition of Boyle's law which states that the Pressure and volume of a gas are inversely proportional if the temperature of the gas remains constant.

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