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Kirsten built a rectangular corral with a fence on three sides.A side of the barn served as a short side od the corral.She used 130 m of fencing . The length of the corral was 20 m longer than the width . Find the dimensions of the corral. Choices for the width : 25, 30 , 35 EXPLAIN

Respuesta :

HouseofForyx
L = W + 20
2L + W = 130

Solve that system with each of the width values. Aka: plug in each w and solve for the length. Whichever  w value gets the same L value for both equations is the answer.

Answer:  Second option is correct.

Step-by-step explanation:

Since we have given that

Let the width of corral be 'w'.

Let the length of corral be 'w+20'

Perimeter of corral = 130 m

As we know the formula for "Perimeter":

[tex]Perimeter=2l+w\\\\130=2(w+20)+w\\\\130=2w+40+w\\\\130=3w+40\\\\130-40=3w\\\\90=3w\\\\\dfrac{90}{3}=w\\\\w=30\ m[/tex]

so, width of corral = 30 m

Length of corral = 30+20 = 50 m

Hence, Second option is correct.

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