Which best describes what happens when 50 mL of 0.0010M CaCl2 is added to 50 mL of 0.010M Na2SO4? (The Ksp of CaSO4 = 2.4 × 10–5.)

Respuesta :

For [Ca +2 ]:
0.0010 mol/l · 0.05 l = [tex]5 * 10^{-5} mol[/tex]
For [ SO4 -2 ] :
0.01 mol/l · 0.05 l = [tex]5 * 10^{-4} [/tex]
Cumulative volume:
 50 ml + 50 ml = 10 ml = 0.1 l
[Ca +2 ] =[tex] \frac{5 * 10^{-5} }{0.1} = 5 * 10^{-4} [/tex]
[SO4 - 2] = [tex] \frac{5*10^{-4} }{0.1}= 5* 10 ^{-3} [/tex]
Qc for CaSO4:
Qc =  [tex]5 * 10 ^{-4} * 5 * 10^{-3} = 25 * 10 ^{-7}= 2.5 * 10 ^{-6} [/tex]
This is less than Ksp of CaSO4. 
 Answer: C ) No precipitation will occur.

Answer:no precipitation occurs

Explanation: