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On Mars, the acceleration due to gravity is 3.77 m / s 2 . 3.77 m/s2. How far would a 15 g 15 g rock fall from rest in 2.5 s 2.5 s if the only force acting on it was the gravitational force due to Mars?

Respuesta :

Answer:

s = 11.78 m

Explanation:

given,

acceleration due to gravity, g = 3.77 m/s²

mass of the rock = 15 g

time = 2.5 s

distance traveled = ?

using equation of motion

[tex]s = ut +\dfrac{1}{2}at^2[/tex]

initial speed = 0 m/s

[tex]s = \dfrac{1}{2}at^2[/tex]

[tex]s = \dfrac{1}{2}\times 3.77 \times 2.5^2[/tex]

s = 11.78 m

distance traveled by the rock is equal to 11.78 m.

Answer:

Explanation:

acceleration, a = 3.77 m/s²

mass, m = 15 g = 0.015 kg

time, t = 2.5 s

Gravitational force, F = mass x acceleration

F = 0.015 x 3.77

F = 0.05655 N

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