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Q10: Putting it all together (0.75 points) Here, we'll update the values in dictionary, storing the output in a dictionary called other_dictionary. This new dictionary will have the same keys, but some values will be updated. The values in other_dictionary should be updated, such that if the value in the original dictionary is... odd: update the the value stored in the dictionary to store the squared difference of the original value and '10'. Remember, you created a function to do this above.) even: store the original value (from dictionary). Hints: to loop through key-value pairs in a dictionary, check out the .items method You created a squared_diff function above.

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ammary456

Answer:

# Code in Python

dictionary={'A':1,'B':2,'C':3,'D':4}

other_dictionary={}

for keys in dictionary:

if dictionary[keys]&1==1:

temp=dictionary[keys]*dictionary[keys]-10*10

other_dictionary[keys]=temp

else:

other_dictionary[keys]=dictionary[keys]

print(other_dictionary)  

assert other_dictionary

Explanation:

  • Initialize a sample example dictionary  and other_dictionary.
  • Do a binary comparision for checking odd number .
  • Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
  • For even: store the original value (from dictionary).

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