Answer:
The sound power (the energy per second) at the threshold of hearing
= 5 x 10^-17 W.
The sound power incident on an eardrum at the threshold of pain
= 5 x 10^-5 W.
Explanation:
The sound power (the energy per second) at the threshold of hearing :
Area of eardrum = 5 x 10^-5 m2
I = Power/Area
Threshold of hearing : I = 1 x 10^-12 W/m2
Power = I x Area = 1 x 10^-12 x 5 x 10^-5 = 5 x 10^-17 W
The sound power incident on an eardrum at the threshold of pain :
Area of eardrum = 5 x 10^-5 m2
I = Power/Area
Threshold of pain = I = 1 W
Power = I x Area = 1 x 5 x 10^-5 = 5 x 10^-5 W
The area of a typical eardrum is about [tex]5.0 * 10^{-5}[/tex]
a) at the threshold of hearing - [tex]5.0 * 10^{-17}[/tex]
(b) at the threshold of pain - [tex]5.0 * 10^{-5}[/tex]
it is the effect of the sound intensity on a certain region of space. This effect varies with the variation in the sound intensity, medium of the region, and the area of the incident region.
1. threshold of hearing
[tex](1.0 * 10^{-12}\ W/m^2)[/tex]
P = x Watt
2. threshold of pain
P =
= [tex]5.0 * 10^{-5}[/tex] joules/sec
= watts
Thus, the area of a typical eardrum is about
a) at the threshold of hearing - [tex]5.0 * 10^{-17}[/tex]
(b) at the threshold of pain - [tex]5.0 * 10^{-5}[/tex]
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