Answer:
Option b
Step-by-step explanation:
Given that the time that a skier takes on a downhill course has a normal distribution with a mean of 12.3 minutes and standard deviation of 0.4 minutes.
If X is the time that the skier takes then
X is N(12.3,0.4)
To convert this to Z score we can use the following
[tex]z=\frac{x-12.3}{0.4}[/tex]
The probability that on a random run the skier takes between 12.1 and 12.5 minutes
=[tex]P(12.1<X<12.5)\\= P(|x-12.3|<0.2)\\=P(|z|<0.5)\\[/tex]
=0.383
Option b is right.
