Respuesta :
Answer:
Explanation:
The electric field is given by
[tex]\overrightarrow{E}=2\times 10^{-11}\widehat{i}-1.20\times 10^{-11}\widehat{j}[/tex]
mass of electron, m = 9.1 x 10^-31 kg
Let a be the acceleration.
u = 2.10 m/s along X axis
time, t = 1.8 s
charge of electron, q = 1.6 x 10^-19 C
Force on electron, F = q E
[tex]\overrightarrow{F}=1.6\times 10^{-19}\left (2\times 10^{-11}\widehat{i}-1.20\times 10^{-11}\widehat{j} \right )[/tex]
[tex]\overrightarrow{F}=\left (3.2\times 10^{-30}\widehat{i}-1.92\times 10^{-30}\widehat{j} \right )[/tex]
a = F / m
[tex]\overrightarrow{a}=\frac{\left (3.2\times 10^{-30}\widehat{i}-1.92\times 10^{-30}\widehat{j} \right )}{9.1\times 10^{-31}}[/tex]
[tex]\overrightarrow{a} = 3.52\widehat{i}-2.12\widehat{j}[/tex]
Use second equation of motion
s = ut + 1/2 at²
[tex]\overrightarrow{s} = 2.10\widehat{i}\times 1.8+0.5\times \left (3.52\widehat{i}-2.12\widehat{j} \right )\times 1.8^{2}[/tex]
[tex]\overrightarrow{s} = 9.48\widehat{i}-3.43\widehat{j}[/tex]
s = (9.48, - 3.43) m
