210 tickets were sold to students
Solution:
Let "a" be the number of normal tickets sold at $ 9 each
Let "b" be the number of student ticket sold at $ 3 discount
Cost of 1 normal ticket = $ 9
Cost of 1 student ticket = $ 9 - $ 3 = $ 6
Yesterday, the movie theater, sold 590 tickets
Which means,
a + b = 590
a = 590 - b ---------- eqn 1
Yesterday, the movie theater,collected a total of $4680
Thus, we frame a equation as:
[tex]a \times 9 + b \times 6 = 4680[/tex]
9a + 6b = 4680 --------- eqn 2
Let us solve eqn 1 and eqn 2
Substitute eqn 1 in eqn 2
9(590 - b) + 6b = 4680
5310 - 9b + 6b = 4680
3b = 630
Divide both sides by 3
b = 210
Thus 210 student tickets were sold
