Answer:
E= 679.83 KJ
Explanation:
Given that
m = 1270 kg
u = 10 km/h
We know that 1 km/h = 0.27 m/s
u = 2.7 m/s
v= 16.67 m/s
h = 40 m
By using energy conservation
The energy required =E
[tex]E=\dfrac{1}{2}m (v^2-u^2)+mgh[/tex]
Now by putting the values in the above equation
[tex]E=\dfrac{1}{2}\times 1270\times (16.67^2-2.7^2)+1270\times 10\times 40[/tex]
We are taking g= 10 m/s²
Now by solving above equation we get
E= 679830.30 J
E= 679.83 KJ
The energy required will be 679.83 KJ
