Respuesta :
Answer:
x ≤ -3 or 2 ≤ x < 7 ;
Step-by-step explanation:
[tex]\frac{x^{2 } + x - 6 }{x - 7 }[/tex] < 0 ;
First we have to factorise the [tex]x^{2} + x - 6[/tex]
[tex]x^{2} + x - 6[/tex] = 0
(x - 2) ( x + 3) = 0
x = 2 $ x = - 3
x - 7 = 0
x = 7
Here we have values of x,
x = - 3 , x = 2 & x = 7
so we can write the solution as follows ;
x ≤ -3
or 2 ≤ x < 7 ;
