Respuesta :
Answer:
a) red wave hs a longer wavelength than the green wave
b)f = 1.875 10¹¹ Hz , f_green = 5.45 10¹⁴Hz
c) E = 1.24 10⁻²² J , E_green = 3.6 10⁻¹⁹ J
d) The red wave is in the infrared range, heat waves
The green wave is in the visible wavelength
Explanation:
a) The green wave are on the left in the electromagnetic spectrum so the red wave has a longer wavelength than the green wave
The green wavelength is in the range of 550 10⁻⁹ m
The speed of the wave is
c = λ f
f = c /λ
b) The frequency of the red wave is
f = 3 10⁸ / 1.6 10⁻³
f = 1.875 10¹¹ Hz
For the green wave
f_green = 3 10⁸/550 10⁻⁹
f_green = 5.45 10¹⁴Hz
c) The photon energy is given by the Planck equation
E = h f
E = 6.63 10⁻³⁴ 1.875 10¹¹
E = 1.24 10⁻²² J
For the green wave
E_green = 6.63 10⁻³⁴ 5.45 10¹⁴
E_green = 3.6 10⁻¹⁹ J
d) The speed of electromagnetic waves is constant and has a value of 3 108 m / s
e)
The red wave is in the infrared range, heat waves
The green wave is in the visible wavelength
a) red has a longer wavelength than the green wave
b) [tex]f=1.875\times 10^{11} \ Hz \ F{green} 5.45\times 10^{14}\ Hz[/tex]
c) [tex]E=1.24\times 10^{-22}\ J E_{green}=3.6\times 10^{-19}J[/tex]
d) The red wave is in the infrared range, heatwaves and The green wave is in the visible wavelength
What will be the condition of the waves calculated?
a) The green wave are on the left in the electromagnetic spectrum so the red wave has a longer wavelength than the green wave
The green wavelength is in the range of [tex]550\times 10^{-9}m[/tex]
The speed of the wave is
[tex]C=\lambda f[/tex]
[tex]f=\dfrac{c}{\lambda }[/tex]
b) The frequency of the red wave is
[tex]f=\dfrac{3\times 10^8}{1.6\times 10^{-3}}[/tex]
[tex]f=1.875\times 10^{11}\ Hz[/tex]
For the green wave
[tex]F_{green}=\dfrac{3\times 10^8}{550\times 10^{-9}} =5.45\times 10^{14}\ Hz[/tex]
c) The photon energy is given by the Planck equation
[tex]E=hf[/tex]
[tex]E=6.63\times 10^{-34}\times 1.875\timnes 10^{11}=1.24\times 10^{-22}J[/tex]
For the green wave
[tex]E_{green}=6.63\times 101^{-34}\times 5.45\times 10^{14}=3.6\times10^{-19}J[/tex]
d) The speed of electromagnetic waves is constant and has a value of [tex]c=3\times10^8[/tex]
e) The red wave is in the infrared range, heat waves
The green wave is in the visible wavelength
Thus
a) red has a longer wavelength than the green wave
b) [tex]f=1.875\times 10^{11} \ Hz \ F{green} 5.45\times 10^{14}\ Hz[/tex]
c) [tex]E=1.24\times 10^{-22}\ J E_{green}=3.6\times 10^{-19}J[/tex]
d) The red wave is in the infrared range, heatwaves and The green wave is in the visible wavelength
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