Respuesta :
Answer:
33 degrees
Step-by-step explanation:
we know that
see the attached figure to better understand the problem
Applying the law of cosines
[tex]QR^2=QS^2+SR^2-2(QS)(SR)cos(S)[/tex]
substitute the given values
[tex]10^2=17^2+18^2-2(17)(18)cos(S)[/tex]
[tex]100=289+324-(612)cos(S)[/tex]
[tex](612)cos (S)=613-100\\cos(S)=513/612\\S=cos^{-1}(513/612)\\S=33^o[/tex]
