Respuesta :
Answer:
The distance between given points is 6.91 units.
Step-by-step explanation:
We are given the following in the question:
[tex]P_1(r,u) = (2.00~m, 50.0^\circ)\\P_2(r,u) = (5.00~m, 250.0^\circ)[/tex]
We convert them into Cartesian coordinate:
[tex]P_1(r,u) = (2.00~m, 50.0^\circ)\\x_1 = 2.00\cos(50^\circ) =1.29\\y_1 = 2.00\sin(50^\circ) = 1.53 \\P_2(r,u) = (5.00~m, 250.0^\circ)\\x_2 = 5.00\cos(250^\circ) =-1.71\\y_1 = 5.00\sin(250^\circ) = -4.7[/tex]
Distance formula between two points:
[tex]\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]
Putting the values, we get
[tex]d = \sqrt{(-1.71-1.29)^2+(-4.7-1.53)^2} = 6.91[/tex]
The distance between given points is 6.91 units.
