Answer: 13 ml of 5.0 M H₂O₂ stock solution that should be used to prepare the solution.
Explanation:
According to the dilution law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock [tex]H_2O_2[/tex] solution = 5.0 M
[tex]V_1[/tex] = volume of stock [tex]H_2O_2[/tex]solution = ?
[tex]M_2[/tex] = molarity of dilute [tex]H_2O_2[/tex] solution = 1.30 M
[tex]V_2[/tex] = volume of dilute [tex]H_2O_2[/tex] solution = 50.0 ml
Putting in the values we get:
[tex]5.0M\times V_2=(1.30M)\times 50.0ml[/tex]
[tex]V_2=13ml[/tex]
Therefore, 13 ml of 5.0 M H₂O₂ stock solution that should be used to prepare the solution.
