Here is a data set:

5
10
10
10
15
100
After studying the data, the researcher realized that the value 100 was meant to be recorded as 15. What happens to the mean and standard deviation of the data set when the 100 is changed to a 15?

v) [tex]standard\hspace{0.15cm}deviation\hspace{0.15cm} of \hspace{0.15cm}data, s = \sqrt{\frac{\sum_{i = 1}^{6} (x_{i} - m)^2}{ (n - 1)}} = \sqrt{\frac{6800}{5} } = 36.88[/tex]

If the last number is changed from 100 to 15 we get :

i) the data is 5, 10, 10, 10, 15, 15

ii) the total number of data, n = 6

iii) sum of the data = 5 + 10 + 10 + 10 + 15 + 15 = 65

iv) mean of data, m = 65 / 6 = 10.83

v) [tex]standard\hspace{0.15cm}deviation\hspace{0.15cm} of \hspace{0.15cm}data, s = \sqrt{\frac{\sum_{i = 1}^{6} (x_{i}-m)^2}{ (n - 1)}} = \sqrt{\frac{70.833}{5} } = 3.764[/tex]

Here is a data set: 5 10 10 10 15 100 After studying the data, the researcher realized that the value 100 was meant to be recorded as 15. What happens to the mean and standard deviation of the data set when the 100 is changed to a 15?

Respuesta :

Otras preguntas

Here is a data set:

5
10
10
10
15
100
After studying the data, the researcher realized that the value 100 was meant to be recorded as 15. What happens to the mean and standard deviation of the data set when the 100 is changed to a 15?