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A ball is kicked with an aim of 35 degrees, measured from the playing field. The ball has initial velocity v0 and lands at a certain point on the field. (Ignore the effects of air.) If the ball had twice the initial velocity, it would_______.

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Answer:

4 times

Explanation:

velocity of projection = vo

angle of projection = 35 degree

The formula for range is given by

[tex]R = \frac{v_{0}^{2}Sin2\theta }{g}[/tex]

Where, θ is the angle of projection

When the velocity becomes doubled, Let the range be R'

So, [tex]R' = \frac{4v_{0}^{2}Sin2\theta }{g}[/tex]

So, R' = 4 R

Thus, the horizontal distance becomes 4 times.

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