Explanation:
According to the figure,
[tex]\vec{p} = q\vec{d}[/tex]
Formula to calculate net dipole moment is as follows.
[tex]\vec{p_{net}} = 2P Cos 52^{o}\hat{i} + (0)\hat{j}[/tex]
[tex]\vec{p_{net}} = 2qd Cos 52^{o}\hat{i}[/tex]
= [tex]2 \times 1.6 \times 10^{-19} \times 0.958 \times 10^{-10} \times Cos 52^{o}\hat{i}[/tex]
= [tex]1.88 \times 10^{-29}\hat{i}[/tex] C-m
Therefore, we can conclude that the net dipole moment for given water molecule is [tex]1.88 \times 10^{-29}\hat{i}[/tex] C-m.
