Answer:
The solution is pulled up the tube
Explanation:
In the figure attached, the Figure 13-2 is shown.
Let's call '1' the beginning of the tube B and '2' the end.
Bernoulli's principle:
[tex] P_1 + \frac{1}{2} \rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2} \rho v_2^2 + \rho g h_2 [/tex]
where P is pressure, ρ is density, v is velocity, h is height and g is the acceleration of gravity
Given that:
- In the spray bottle the pressure at 2 is lower than at 1.
- The velocity is constant through the tube
Then h2 must be greater than h1, so the solution is pulled up the tube
