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To analyze the experiment used to determine the properties of an electron. In 1909, Robert Millikan performed an experiment involving tiny, charged drops of oil. The drops were charged because they had picked up extra electrons. Millikan was able to measure the charge on each drop in coulombs. Here is an example of what his data may have looked like. Based on the given data, how many extra electrons did drop C contain? a. 3.20 x10^{-19}b. 4.80 x10^{-19}c. 8.00 x 10^{-19}d. 9.60 x 10^{-19}

Respuesta :

Answer:

C has 5 electrons

Explanation:

Given:

The data acquired from the experiment performed by Millikan:

Q_a = 3.20 x10^{-19}  C

Q_b = 4.80 x10^{-19}  C

Q_c = 8.00 x 10^{-19}  C

Q_d = 9.60 x 10^{-19}  C

Find:

How many Electrons were present in drop C

Solution:

It is known that the charge of an electron e = 1.602 *10^-19 C / electron.

Hence the number of electrons n in drop C will be:

      n = Q_c / e

      n = 8.00 x 10^{-19}  / 1.602*10^-19

      n = 4.99 = 5 electrons  

Answer: The drop C contains 5 electrons.