Respuesta :
The question is incomplete, here is the complete question:
A chemist prepares a solution of iron (III) bromide [tex](FeBr_3)[/tex] by measuring out 2.78 g of iron (III) bromide into a 50. mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mmol/L of the chemists iron (III) bromide solution. Be sure your answer has the correct number of significant digits.
Answer: The concentration of iron(III) bromide solution is 0.19 M
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
We are given:
Given mass of iron(III) bromide = 2.78 g
Molar mass of iron(III) bromide = 298.6 g/mol
Volume of solution = 50. mL
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{2.78\times 1000}{298.6\times 50}\\\\\text{Molarity of solution}=0.19M[/tex]
Hence, the concentration of iron(III) bromide solution is 0.19 M
