You dissolve 10 grams of sugar in a hundred mL of water in one container and another 10 grams of sugar and 500 mL of water in a different container which one would taste sweeter? Why?

Respuesta :

10 g of sugar in 100 ml of water is sweeter.

Explanation:

We need to find the concentration of the two solutions from that we can find which one is dilute and which one is concentrated solution.

Concentration is given in terms of molarity (M) = moles/L

Moles can be found by dividing the given mass by the molar mass of the sugar (342.3 g/mol)

Now we can find the molarity as,

1. 100 ml = 0.1 L

moles = 10 g / 342.3 g / mol = 0.029 moles

molarity = 0.029 moles / 0.1 L = 0.29 M

2. molarity = 0.029 / 0.5 L = 0.058 M

So first solution is more concentrated, and also taste sweeter than the second solution.

10 g of sugar in 100 ml of water is more sweeter.

Calculation for concentration:

Molarity is defined as number of moles of solute over volume of solution in litres.

So, concentration is given in terms of molarity (M) = moles / L

Number of moles is given mass over molar mass:

Molar mass of sugar = 342.3 g/mol

Number of moles= 10 g / 342.3 g / mol

Number of moles = 0.029 moles

Molarity for two solutions will be:

Molarity = 0.029 moles / 0.1 L

Molarity = 0.29 M

Molarity = 0.029 / 0.5 L

Molarity  = 0.058 M

So, first solution is more concentrated, and also taste sweeter than the second solution.

Find more information about Molarity here:

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