Answer : The final velocity of the ball is, 12.03 m/s
Explanation :
By the 3rd equation of motion,
[tex]v^2-u^2=2as[/tex]
where,
s = distance covered by the object = 6.93 m
u = initial velocity  = 2.99 m/s
v = final velocity = ?
a = acceleration = [tex]9.8m/s^2[/tex]
Now put all the given values in the above equation, we get the final velocity of the ball.
[tex]v^2-(2.99m/s)^2=2\times (9.8m/s^2)\times (6.93m)[/tex]
[tex]v=12.03m/s[/tex]
Thus, the final velocity of the ball is, 12.03 m/s
