contestada

A hospital worker combined 2 fluidounces of a povidone–iodine cleaner, 7.5% w/v, with 4 fluidounces of a povidone–iodine topical solution, 10 % w/v. Calculate the resulting strength of the povidone–iodine mixture.

Respuesta :

danialamin

Answer:

The concentration of resultant mixture is 9.167% w/v

Step-by-step explanation:

The mixture contains  

  • 2 fluid-ounces of a povidone–iodine cleaner, 7.5% w/v  
  • 4 fluid-ounces of a povidone–iodine topical solution, 10 % w/v.

The resulting concentration is given as

[tex][c]=\frac{c1w1 +c2w2}{w1+w2}[/tex]

Here

c1=7.5% w/v

c2=10% w/v

w1=2 fluid ounces

w2=4 fluid ounces

Substituting values gives

[tex]c=\frac{c1w1 +c2w2}{w1+w2}\\c=\frac{7.5 \times 2 +10 \times 4}{2+4} \\c=\frac{15 +40}{6} \\c=\frac{55}{6} \\c=9.167 w/v[/tex]

So the concentration of resultant mixture is 9.167% w/v

raphealnwobi

The resulting strength of the povidone–iodine mixture is 9.17% of 6 fluidounces of povidone–iodine mixture.

Since 2 fluidounces of a povidone–iodine is combined with 4 fluidounces of a povidone–iodine topical solution, the resulting mixture would be (2 + 4) = 6 fluidounces of a povidone–iodine topical solution.

Let y represent the resulting strength of the povidone–iodine mixture.

Therefore:

2 * 7.5% + 4 * 10% = 6 * y

0.15 + 0.4 = 6y

0.55 = 6y

y = 0.0917

y = 9.17%

Hence the resulting strength of the povidone–iodine mixture is 9.17% of 6 fluidounces of povidone–iodine mixture.

Find out more at: https://brainly.com/question/24713315

Otras preguntas