A bourdon pressure gage attached to the outside of a tank containingair reads 77.0psi when the local atmospheric pressure is 760 mmHg. What will be the gage reading if the atmospheric pressure increases to 773 mmHg?

Respuesta :

Answer:

The gage reading when the atmospheric pressure increases to 773 mmHg is 77.3 psi

Explanation:

[tex]P_{abs} = P_{gauge}+P_{atm}[/tex]

where;

[tex]P_{abs}[/tex] is absolute pressure in Psi

[tex]P_{gauge}[/tex] is the gauge pressure in Psi

[tex]P_{atm}[/tex] is the atmospheric pressure in Psi

Given;

Absolute pressure = 77 psi

Atmospheric pressure = 760 mmHg = 1 atm = 14.7 psi

From the equation above, Gauge pressure is:

[tex]P_{gauge} = P_{abs}-P_{atm}[/tex] = 77 - 14.7 = 62.3 psi

Gauge pressure is 62.3 psi

⇒When the Atmospheric pressure increases to 773 mmHg:

773 mmHg = 1.0171053 atm = 14.947 psi

[tex]P_{gauge}[/tex] = 62.3 psi, [tex]P_{atm}[/tex] = 14.947 psi

[tex]P_{abs} = P_{gauge}+P_{atm}[/tex]

      = 62.3 + 14.947

      = 77.247 psi

       ≅ 77.3 psi

Therefore, the gage reading when the atmospheric pressure increases to 773 mmHg is 77.3 psi