To solve this problem we will apply the concepts of speed given the simple harmonic movement, for which it defines this speed as
[tex]v_{max} = \omega A[/tex]
Here
[tex]\omega =[/tex]Angular velocity
A = Amplitude
Recall that the angular velocity is equivalent in terms of the frequency at
[tex]\omega = 2\pi f[/tex]
If we replace the value we will have then
[tex]v_{max} = 2\pi f A[/tex]
For mass A
[tex]v_{max,A} = 2\pi (10)(0.08) = 5.024m/s[/tex]
For mass B
[tex]v_{max.B} = 2\pi (16)(0.05) = 5.024m/s[/tex]
Therefore they are equal.
