Respuesta :
Answer:
None of the above statements is true.
That's the correct stement since none of the answers provided are correct
Step-by-step explanation:
For this case we know that the average for starting salary last year was 39000 and this value is calculated from the following formula:
[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n} = 39000[/tex]
And this average refer to the sample and we need to select one of the following options:
Last year some of their clients had a starting salary of exactly $39,000.
False we can have values totally different from 39000 and when we compute the average we can have the average or mean equal to 39000
Two years ago at least one of their clients had a starting salary of at least $39,000.
False we can have values lower than 39000 and we can have also the mean 39000.
Last year more than half of their clients had a starting salary of at least $39,000.
False we can have less than half of the values <39000 and the remaining values high enough to ensure that the mean is 39000
Last year all of their clients had a starting salary of less than $43,000.
False we can have more than half of the values >43000 and the remaining values low enough to ensure that the mean is 39000
None of the above statements is true.
That's the correct stement since none of the answers provided are correct
