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A room in the lower level of a cruise ship has a 30 cm diameter circular window If the midpoint of the window is 4 m below the water surface, determine the hydrostatic force in Newtons acting on the window. Answer 2840N.

Respuesta :

Answer:

F = 2840.3 N

Explanation:

Given:

- Diameter of window D = 0.3 m

- Midpoint of window from sea level h = 4 m

- Specific gravity of sea water S.G = 1.024

- Density of water p = 1000 kg/m^3

Find:

The hydro-static force F_r acting on the mid-point of the window.

Solution:

- The average pressure P acting on the midpoint of the window:

                               P = S.G p*g*h

                               P = 1.024*1000*9.81*4

                               P = 40181.76

- The hydro-static force F_r acting on the mid-point of the window:

                               F = P*A = P*pi*D^2 / 4

                               F = 40181.76*pi*0.3^2 / 4

                               F = 2840.3 N

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