Respuesta :
Answer : The balanced complete and net ionic equations are written below.
Explanation :
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a) The balanced molecular equation will be,
[tex]FeCl_3(aq)+Cs_3PO_4(aq)\rightarrow 3CsCl(aq)+FePO_4(s)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]Fe^{3+}(aq)+3Cl^{-}(aq)+3Cs^{+}(aq)+PO_4^{3-}(aq)\rightarrow 3Cs^{+}(aq)+3Cl^{-}(aq)+FePO_4(s)[/tex]
In this equation the species present are, [tex]3Cl^{-}\text{ and }Cs^{+}[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]Fe^{3+}(aq)+PO_4^{3-}(aq)\rightarrow FePO_4(s)[/tex]
(b) The balanced molecular equation will be,
[tex]2NaOH(aq)+Cd(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Cd(OH)_2(s)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]2Na^{+}(aq)+2OH^{-}(aq)+Cd^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+Cd(OH)_2(s)[/tex]
In this equation the species present are, [tex]Na^{+}\text{ and }NO_3^{-}[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]Cd^{2+}(aq)+2OH^{-}(aq)\rightarrow Cd(OH)_2(s)[/tex]
(c) The balanced molecular equation will be,
[tex]MgBr_2(aq)+2CH_3COOK(aq)\rightarrow (CH_3COO)_2Mg(aq)+2KBr(aq)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]Mg^{2+}(aq)+2Br^{-}(aq)+2K^{+}(aq)+2CH_3COO^{-}(aq)\rightarrow Mg^{2+}(aq)+2CH_3COO^{-}(aq)+2Br^{-}(aq)+2K^{+}(aq)[/tex]
In this equation all the species are the spectator ions.
Thus, there is no net ionic equation.
(d) The balanced molecular equation will be,
[tex]Ag_2SO_4(aq)+BaCl_2(aq)\rightarrow 2AgCl(s)+BaSO_4(s)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]2Ag^{+}(aq)+SO_4^{2-}(aq)+Ba^{2+}(aq)+2Cl^{-}(aq)\rightarrow 2AgCl(s)+BaSO_4(s)[/tex]
In this equation no species are the spectator ions.
Thus, there is no net ionic equation.
(e) The balanced molecular equation will be,
[tex]Na_2SO_4(aq)+Sr(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+SrSO_4(s)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]2Na^{+}(aq)+SO_4^{2-}(aq)+Sr^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+SrSO_4(s)[/tex]
In this equation the species present are, [tex]Na^{+}\text{ and }NO_3^{-}[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]Sr^{2+}(aq)+SO_4^{2-}(aq)\rightarrow SrSO_4(s)[/tex]
The balanced chemical reaction equation demonstrates the reaction that took place.
A reaction occurs when new products are formed. We shall now proceed to look into each case to know if a chemical reaction is possible or not.
- FeCl3(aq) + Cs3(PO4) (aq) ------> 3CsCl(aq) + FePO4(aq)
- 2NaOH(aq) + Cd(NO3)2(aq) -------> 2NaNO3(aq) + Cd(OH)2(s)
- MgBr2(aq) + 2CH3COOK(aq) -----> 2KBr(aq) + Mg(CH3COO)2(s)
- Ag2SO4(aq) + BaCl2(aq) ---------> BaSO4(s) + 2AgCl
- Na2SO4(aq) + Sr(NO3)2(aq) ------> 2NaNO3(aq) + SrSO4(s)
Hence, the balanced chemical reaction equation demonstrates the reaction that took place.
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