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Two submarines are underwater and approaching each other head-on.Sub A has a speed of 4 m/s and sub B has aspeed of 14 m/s. Sub A sends out a1910 Hz sonar wave that travels at a speedof 1522 m/s.(a) What is the frequency of the sound detected by subB (to the nearest Hz)?Hz(b) Part of the sonar wave is reflected from B and returns to A.What frequency does A detect for this reflected wave (to thenearest Hz)?Hz

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Answer:

1933 Hz

1956 Hz

Explanation:

[tex]v_0[/tex] = Velocity of object

[tex]v_s[/tex] = Velocity of source

v = Velocity of sound

From Doppler effect

[tex]f=f'\dfrac{v+v_0}{v-v_s}\\\Rightarrow f=1910\dfrac{1522+14}{1522-4}\\\Rightarrow f=1932.64822134\ Hz=1933\ Hz[/tex]

The frequency of the sound detected by subB is 1933 Hz

[tex]f=f'\dfrac{v+v_0}{v-v_s}\\\Rightarrow f=1932.64822134\dfrac{1522+4}{1522-14}\\\Rightarrow f=1955.7169\ Hz=1956\ Hz[/tex]

The frequency of the sound detected by subA is 1956 Hz

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