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Given a normal distribution of scores with µ = 85 and σ = 17.5, what raw score lies at the upper boundary of the interval that includes scores within one standard deviation of the mean?

Respuesta :

Answer:

x  = 102.5

Explanation:

given,

mean of the normal distribution curve,  µ = 85

standard deviation, σ = 17.5

z -score = 1

now, using formula of z-score

[tex]Z = \dfrac{x-\mu}{\sigma}[/tex]

[tex]1 = \dfrac{x-85}{17.5}[/tex]

   x - 85 = 17.5

   x = 17.5 +85

    x  = 102.5

hence, the upper bound value for the 1 standard deviation is equal to 102.5.

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