Answer:
The electric force on the top charge is [tex]F=3.44\times 10^6\ N[/tex].
Explanation:
Given that,
Electric charges in a thundercloud, [tex]q_1=q_2=45\ C[/tex]
The distance between charges, d = 2.3 km = 2300 m
Let F is the electric force on the top charge. The electric force is given by the formula as :
[tex]F=\dfrac{kq^2}{d^2}[/tex]
[tex]F=\dfrac{9\times 10^9\times (45)^2}{(2300)^2}[/tex]
[tex]F=3445179.58\ N[/tex]
or
[tex]F=3.44\times 10^6\ N[/tex]
So, the electric force on the top charge is [tex]F=3.44\times 10^6\ N[/tex]. Hence, this is the required solution.
