Answer:
The equation for the distance Jane's trainer bikes is [tex]x=\sqrt{16^2+12^2}[/tex].
Step-by-step explanation:
We have attached diagram for your reference.
Given:
Distance traveled on bike towards south = 16 miles
Distance she ran towards west = 12 miles
We need to find distance Jane's trainer bikes.
Solution:
Let the distance Jane's trainer bike be 'x'.
Now we will assume it to be right angled triangle.
So by Pythagoras theorem which states that;
"Square of the third side is equal to the sum of square of the other two sides."
framing in equation form we get;
[tex]x^2=16^2+12^2\\\\x=\sqrt{16^2+12^2}[/tex]
Hence the equation for the distance Jane's trainer bikes is [tex]x=\sqrt{16^2+12^2}[/tex].
On solving we get;
[tex]x=\sqrt{16^2+12^2}\\\\x= \sqrt{256+144}\\ \\x=\sqrt{400} \\\\x=20\ miles[/tex]
Hence Jane's trainer bikes a distance of 20 miles.
The distance Jane's trainer bikes to her is 20 miles.
In order to determine distance Jane's trainer bikes to her, we have to determine the value of the hypotenuse of the triangle formed when Jane bikes to the south and then to the east.
The Pythagoras theorem: a² + b² = c²
where
√16² + 12²
=√ 256 + 144
= √400
= 20 miles
Please find attached an image of cardinal points. To learn more about Pythagoras theorem, please check: brainly.com/question/20936855
