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Part of the proceeds from a garage sale was $470 worth of $10 and $20 bills. If there were 14 more $10 bills than $20 bills, find the number of each denomination There were $10 bills and $ 20 bills

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absor201

There are 25 $10 bills and 11 $20 bills.

Step-by-step explanation:

Given,

Worth of proceeds from garage = $470

Let,

x be the number of $10 bills

y be the number of $20 bills.

According to given situation;

10x+20y=470       Eqn 1

x = y+14                Eqn 2

Putting value of x from Eqn 2 in Eqn 1

[tex]10(y+14)+20y=470\\10y+140+20y=470\\30y=470-140\\30y=330[/tex]

Dividing both sides by 30

[tex]\frac{30y}{30}=\frac{330}{30}\\y=11[/tex]

Putting y=11 in Eqn 2

[tex]x=11+14\\x=25[/tex]

There are 25 $10 bills and 11 $20 bills.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/1279756
  • brainly.com/question/1284310

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