Answer:
81.8 %
Explanation:
The balanced equation for the reaction is [tex]3H_2 + N_2[/tex] ⇒ [tex]2 NH_3[/tex]
So to find the number of moles of [tex]H_2[/tex] we do 6.04kg ÷ 2 = 3.02 moles.
The mole ratio between [tex]H_2[/tex] and [tex]NH_3[/tex] is 3:2. So to find the number of moles you do [tex]\frac{3.02}{3}[/tex] × 2 which gives you 2.0124 moles.
Then you find the mass by doing moles multiplied by Mr: 2.0124 x 17 which gives you 34.21 kg.
Then to find the percentage yield you do: [tex]\frac{28}{34.21}[/tex] x 100 = 81.82.......
Which is 81.8 %
