Answer:
the initial temperature is T initial = 53.5 °C
Explanation:
the heat lost Q by ethylene glycol is
Q= m* c * ( T final - T initial )
where
m = mass of ethylene glycol = 10.5 g
c = specific heat capacity of ethylene glycol = 2.42 J/g*°C
T final = final temperature = 32.5°C
T initial = initial temperature
Q = heat lost = (-546 J) ( negative sign means lose of energy)
solving for T initial
Q= m* c * ( T final - T initial )
T initial = T final- Q/(m* c)
replacing values
T initial = T final- Q/(m* c) = 32.5°C - (-546 J)/(10.5 g * 2.42 J/g*°C) = 53.5 °C
T initial = 53.5 °C
then the initial temperature is T initial = 53.5 °C
