A merchant mixed 8 lb of a cinnamon tea with 6 lb of spice tea. The 14-pound mixture cost $38. A second mixture included 16 lb of the cinnamon tea and 10 lb of the spice tea. The 26-pound mixture cost $70. Find the cost per pound of the cinnamon tea and of the spice tea.

Respuesta :

Answer:

The cost of cinnamon tea per pound is $2.5

The cost of spice tea per pound is $ 3

Step-by-step explanation:

Let the cost of cinnamon tea per pound be x

Let the cost of spice tea per pound be  y

Then according to the question:

A merchant mixed 8 lb of a cinnamon tea with 6 lb of spice tea. and its cost is $38

Then,

8x + 6y  = 38-------------------------------(1)

A second mixture included 16 lb of the cinnamon tea and 10 lb of the spice tea. The 26-pound mixture cost $70

16x + 10y = 70----------------------------(2)

To Solving (1) and (2)

Multiply (1) by 2 then

16x +  12y = 76-----------------------------(3)

Subtracting (2) from (3)

16x +  12y = 76

16x + 10y = 70

------------------------

0x + 2y = 6

-------------------------

[tex]y = \frac{6}{2}[/tex]

y =  3

On substituting y  value in eq(1)

8x + 6(3)  = 38

8 x + 18 = 38

8x = 38 -18

8x  =  20

[tex]x = \frac{ 20}{8}[/tex]

x = 2.5